document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36365>Question 36365</A>: <I><SPAN STYLE=\"word-break: break-all;\">   (b)	Find the equation of the sphere, which contains the circle<BR>\n" );
document.write( "	x^2 + y^2 + z^2 = 9, 3x + 3y + 3z = 5   and<BR>\n" );
document.write( "	passes through the origin. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22506 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  (b) Find the equation of the sphere, which contains the circle<BR>\n" );
document.write( "x^2 + y^2 + z^2 = 9, 3x + 3y + 3z = 5 and passes through the origin. <BR>\n" );
document.write( " THAT IS CONTAINS CIRCLE<BR>\n" );
document.write( "x^2 + y^2 + z^2 - 9=0=P SAY ,AND  3x + 3y + 3z - 5 =0=L SAY<BR>\n" );
document.write( "ANY SPHERE THROUGH THE ABOVE CIRCLE IS GIVEN BY<BR>\n" );
document.write( "P+KL=0...WHERE K IS A CONSTANT TO BE FOUND..WE ARE GIVEN IT PASSES THROUGH ORIGIN.HENCE<BR>\n" );
document.write( "0^2+0^2+0^2-9+K(0+0+0-5)=0<BR>\n" );
document.write( "-9-5K=0...........5K=-9<BR>\n" );
document.write( "K=-9/5<BR>\n" );
document.write( "HENCE EQN OF SPHERE IS <BR>\n" );
document.write( "5(X^2+Y^2+Z^2-9)-9(3X+3Y+3Z-5)=0<BR>\n" );
document.write( "5X^2+5Y^2+5Z^2-45-27X-27Y-27Z+45=0<BR>\n" );
document.write( "5X^2+5Y^2+5Z^2-27X-27Y-27Z=0 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );