document.write( "Question 314693: Find three consecutive odd integers such that the square of the second added to the first is seventy five less than the square of the third.
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Algebra.Com's Answer #225055 by checkley77(12844)\"\" \"About 
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Let x, x+2 & x+4 be the 3 integers.
\n" ); document.write( "(x+2)^2+x=(x+4)^2-75
\n" ); document.write( "x^2+4x+4+x=x^2+8x+16-75
\n" ); document.write( "x^2-x^2+5x-8x=-4+16-75
\n" ); document.write( "-3x=-63
\n" ); document.write( "x=-63/-3
\n" ); document.write( "x=21 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "(21+2)^2+21=(21+4)^2-75
\n" ); document.write( "23^2+21=25^2-75
\n" ); document.write( "529+21=625-75
\n" ); document.write( "550=550
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