document.write( "Question 314693: Find three consecutive odd integers such that the square of the second added to the first is seventy five less than the square of the third.
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Algebra.Com's Answer #225055 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Let x, x+2 & x+4 be the 3 integers. \n" ); document.write( "(x+2)^2+x=(x+4)^2-75 \n" ); document.write( "x^2+4x+4+x=x^2+8x+16-75 \n" ); document.write( "x^2-x^2+5x-8x=-4+16-75 \n" ); document.write( "-3x=-63 \n" ); document.write( "x=-63/-3 \n" ); document.write( "x=21 ans. \n" ); document.write( "Proof: \n" ); document.write( "(21+2)^2+21=(21+4)^2-75 \n" ); document.write( "23^2+21=25^2-75 \n" ); document.write( "529+21=625-75 \n" ); document.write( "550=550 \n" ); document.write( " |