document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314688>Question 314688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write and solve an equation to determine the value of a $8000 investment if it is invested for 3 years at 3.5% compunded annually. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225046 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We use A = P times (1 + r)^(number of years)\r<BR>\n" );
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document.write( "A = P(1 + r)^n\r<BR>\n" );
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document.write( "A = 8000(1 + 0.035)^3\r<BR>\n" );
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document.write( "A = 8000(1.035)^3\r<BR>\n" );
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document.write( "A = 8000(1.108717875)\r<BR>\n" );
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document.write( "A = $8869.743\r<BR>\n" );
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document.write( "You can round answer off to the nearest hundreths.  In that case, A = $8869.74 </SPAN>\n" );
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