document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314657>Question 314657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is  6 yards longer than its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is 52 yards find its area.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #225023 by </B><A HREF=/tutors/aboutme.mpl?userid=Jstrasner><B>Jstrasner(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jstrasner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jstrasner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=225023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hey, \r<BR>\n" );
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document.write( "So for this one, we simply need to write what we know down:\r<BR>\n" );
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document.write( "for the perimeter:\r<BR>\n" );
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document.write( "2L + 2W = 52 yards\r<BR>\n" );
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document.write( "for the info:\r<BR>\n" );
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document.write( "L = W + 6\r<BR>\n" );
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document.write( "We can substitute L in the equation for W + 6:\r<BR>\n" );
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document.write( "2(W+6) + 2W =52 \r<BR>\n" );
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document.write( "2W + 12 + 2W =52\r<BR>\n" );
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document.write( "4W + 12 = 52\r<BR>\n" );
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document.write( "4W = 40\r<BR>\n" );
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document.write( "W = 10\r<BR>\n" );
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document.write( "then we subsitute W into the original equation:\r<BR>\n" );
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document.write( "L = 10 + 6\r<BR>\n" );
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document.write( "L = 16\r<BR>\n" );
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document.write( "Area is length multiplied by width:\r<BR>\n" );
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document.write( "A=L*W\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "A= 16*10   =>   160 yards^2\r<BR>\n" );
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document.write( "I hope this helps! </SPAN>\n" );
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