document.write( "Question 314650: fint the distance(-3,7)(6,-4) \n" ); document.write( "

Algebra.Com's Answer #225017 by Jstrasner(112) $\"\"$ $\"About$

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Hey,\r
\n" ); document.write( "\n" ); document.write( "Well for this question you need to find the hypotenuse of the triangle that the two coordinates make. \r
\n" ); document.write( "\n" ); document.write( "You need to find the lengths of the two bases to find the length of the hypotenuse(distance) using the pythagorean theorem: a^2 + b^2 = c^2\r
\n" ); document.write( "\n" ); document.write( "So to find the vertical one, we use the y coordinates 7 and -4:\r
\n" ); document.write( "\n" ); document.write( "7-(-4) => 7+4=11\r
\n" ); document.write( "\n" ); document.write( "And then we use the x coordinates to find the horizontal one with -3 and 6:\r
\n" ); document.write( "\n" ); document.write( "6-(-3)=6+3=9 \r
\n" ); document.write( "\n" ); document.write( "So we plug these into the theorem:\r
\n" ); document.write( "\n" ); document.write( "9^2 + 11^2 = c^2 => 81 + 121 = 202 => c^2 = 202 \r
\n" ); document.write( "\n" ); document.write( "Find the square root of both sides and you get:14.21...Which is the distance\r
\n" ); document.write( "\n" ); document.write( "I hope this helps!\r
\n" ); document.write( "\n" ); document.write( "c= \n" ); document.write( "

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