document.write( "Question 314609: The length of a rectangle is five more than twice the width. If the perimeter is 70 feet, find the length? \n" ); document.write( "
Algebra.Com's Answer #224969 by texttutoring(324)\"\" \"About 
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Let l=length and w=width\r
\n" ); document.write( "\n" ); document.write( "The formula for perimeter is P=2l+2w and we know that l=2w+5\r
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\n" ); document.write( "\n" ); document.write( "70=2l+2w\r
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\n" ); document.write( "\n" ); document.write( "Now replace the l with 2w+5\r
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\n" ); document.write( "\n" ); document.write( "70=2(2w+5) + 2w
\n" ); document.write( "70=4w+10+2w
\n" ); document.write( "70=6w+10
\n" ); document.write( "60=6w
\n" ); document.write( "w=10\r
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\n" ); document.write( "\n" ); document.write( "l=2w+5
\n" ); document.write( "l=2(10)+5
\n" ); document.write( "l=25\r
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\n" ); document.write( "\n" ); document.write( "So the width is 10, and the length is 25.
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