document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314533>Question 314533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if mike is 4 years older than tom and five years ago mike was twice toms age how old is tom now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224907 by </B><A HREF=/tutors/aboutme.mpl?userid=eshomali><B>eshomali(33)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=eshomali><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=eshomali><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tom has to be the age of -9 and Mike has to be the age of -13. That is the only way for it to work, in real life, its impossible because you cannot be of negitive age. consider this equation:\r<BR>\n" );
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document.write( "A is Tom<BR>\n" );
document.write( "B is Mike\r<BR>\n" );
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document.write( "using system equations of:\r<BR>\n" );
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document.write( "A + 4 = B<BR>\n" );
document.write( "B - 5 = 2A\r<BR>\n" );
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document.write( "Solve for B in the second equation, and plug the solved B into the first equation to find A. Done and Done. </SPAN>\n" );
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