document.write( "Question 314531: In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1/5 hour longer. How far did she travel to the appointment? \n" ); document.write( "
Algebra.Com's Answer #224902 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=50T \n" ); document.write( "D=40(T+.2) \n" ); document.write( "50T=40(T-.2) \n" ); document.write( "50T=40T+.8 \n" ); document.write( "50T-40T=8 \n" ); document.write( "10T=8 \n" ); document.write( "T=8/10 \n" ); document.write( "T=.8 HOURS OR 48 MINUTES. \n" ); document.write( "50*.8=40 MILES IS THE DISTANCE. \n" ); document.write( "40(.8+.2)=40*1=40 MILES. \n" ); document.write( " |