document.write( "Question 314531: In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1/5 hour longer. How far did she travel to the appointment? \n" ); document.write( "
Algebra.Com's Answer #224902 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "D=50T
\n" ); document.write( "D=40(T+.2)
\n" ); document.write( "50T=40(T-.2)
\n" ); document.write( "50T=40T+.8
\n" ); document.write( "50T-40T=8
\n" ); document.write( "10T=8
\n" ); document.write( "T=8/10
\n" ); document.write( "T=.8 HOURS OR 48 MINUTES.
\n" ); document.write( "50*.8=40 MILES IS THE DISTANCE.
\n" ); document.write( "40(.8+.2)=40*1=40 MILES.
\n" ); document.write( "
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