document.write( "Question 4736: Find the inverse of the given function. f(x) = squareroot of (x-10).\r
\n" ); document.write( "\n" ); document.write( "Is there a solver for inverse functions?\r
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Algebra.Com's Answer #2249 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+sqrt+%28x-10%29+\" or
\n" ); document.write( "\"+y+=+sqrt+%28x+-+10%29+\"\r
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\n" ); document.write( "\n" ); document.write( "To find the inverse function,
\n" ); document.write( "STEP 1: interchange the x and y, and
\n" ); document.write( "STEP 2: solve for y.\r
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\n" ); document.write( "\n" ); document.write( "STEP 1: \"x+=+sqrt+%28y+-10%29+\"\r
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\n" ); document.write( "\n" ); document.write( "STEP 2: Square both sides:
\n" ); document.write( "\"x%5E2+=+y-+10+\"\r
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\n" ); document.write( "\n" ); document.write( "Add 10 to each side:
\n" ); document.write( "\"x%5E2+%2B+10+=+y\"\r
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\n" ); document.write( "\n" ); document.write( "This \"y+=+x%5E2+%2B+10+\" is the inverse function
\n" ); document.write( "So, \"f%5E%28-1%29+=+x%5E2+%2B+10+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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