document.write( "Question 314490: Solve for z: 2/3= 3z+4/2z\r
\n" ); document.write( "\n" ); document.write( "I got z= -12/5, but I wanted to double check that it was correct! :)\r
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Algebra.Com's Answer #224858 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
You can always verify your solution by using the original equation and sticking in the value,
\n" ); document.write( "\"2%2F3=+%283z%2B4%29%2F2z\"
\n" ); document.write( "\"2%2F3=%283%28-12%2F5%29%2B4%29%2F%282%28-12%2F5%29%29\"
\n" ); document.write( "\"2%2F3=%28%28-36%2F5%29%2B20%2F5%29%2F%28-24%2F5%29%29\"
\n" ); document.write( "\"2%2F3=%28-16%2F5%29%2F%28-24%2F5%29\"
\n" ); document.write( "\"2%2F3=16%2F24\"
\n" ); document.write( "\"2%2F3=2%2F3\"
\n" ); document.write( "Yes, your solution is correct.
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