document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314471>Question 314471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An automobile travels from point A to point B at a speed of 40 km/h. How fast must it travel in the opposite direction to achieve an average speed of 50 km/h for the round trip?\r<BR>\n" );
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document.write( "(A) 50 km/h (B) 58 km/h (C) 60 km/h (D) 66• km/h (E) Not enough<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224844 by </B><A HREF=/tutors/aboutme.mpl?userid=malaydassharma><B>malaydassharma(59)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malaydassharma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=malaydassharma><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the distance between A and B is 40 Km.<BR>\n" );
document.write( "Hence, Total distance covered in journey=40+40=80 Km<BR>\n" );
document.write( "Average Speed = 50 Km/hr\r<BR>\n" );
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document.write( "Therefore, avg time required for the totaltrip= 80/50= 1 3/5 Hrs<BR>\n" );
document.write( "As 1 hr is aleady used during onward journey, remaining time for return journey is 1 3/5 -1 = 3/5 Hrs.for travelling back 40 Kms from B to A.\r<BR>\n" );
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document.write( "Hence, Speed = 40 / (3/5)=200/3=66.66 Km/Hr   [ Ans(D)]\r<BR>\n" );
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