document.write( "Question 36552: The sum of a geometric series is 57232. The common ratio is 2 and the last term is 28672. What is the first term? \n" ); document.write( "
Algebra.Com's Answer #22483 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! The sum of a geometric series is 57232. The common ratio is 2 and the last term is 28672. What is the first term? \n" ); document.write( "FORMULA FOR N TH TERM IS .... \n" ); document.write( "TN=A*R^(N-1)..HENCE \n" ); document.write( "28672=A*2^(N-1).......................I \n" ); document.write( "FORMULA FOR SUM IS \n" ); document.write( "SN=A*{R^N - 1 }/(R-1)...HENCE \n" ); document.write( "57232 = A*(2^N-1)/(2-1)=A*(2^N-1)....................II \n" ); document.write( "EQN.II/EQN.I... \n" ); document.write( "57232/28672=A*(2^N -1)/{A*2^(N-1)}=(2^N -1)/2^(N-1) \n" ); document.write( "57232/28672=2^N/2^(N-1) - 1/2^(N-1)=2-1/2^(N-1) \n" ); document.write( "1/2^(N-1)=2-57232/28672=(57344-57232)/28672=112/28672 \n" ); document.write( "2^(N-1)=28672/112=256=2^7 \n" ); document.write( "N-1=7….OR……N=8…SUBSTITUTING IN EQN.I… \n" ); document.write( "28672=A*2^(8-1)=256A…..OR…..A = 28672/256=112 \n" ); document.write( " |