document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314412>Question 314412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor: a^3-2a^2-a+2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224801 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, this is going to be solved like a Quadratic Equation, but first you will have to FACTOR this by GROUPING.\r<BR>\n" );
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document.write( "a^3-2a^2-a+2=0<BR>\n" );
document.write( "From the first two terms, take out a common factor of a^2, and from the last two terms take out a factor of -1.<BR>\n" );
document.write( "a^2(a-2)-1(a-2)=0\r<BR>\n" );
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document.write( "Now take out the common factor of (a-2):<BR>\n" );
document.write( "(a-2)(a^2-1)=0<BR>\n" );
document.write( "(a-2)(a-1)(a+1)=0\r<BR>\n" );
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document.write( "There are 3 solutions:<BR>\n" );
document.write( "a=2, a=1, and a=-1\r<BR>\n" );
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document.write( "Dr. Rapalje </SPAN>\n" );
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