document.write( "Question 314421: Please help with this question.
\n" ); document.write( "A water rocket is launched upward with an initial velocity of 48 ft/sec. It's height h, in ft after t seconds is given by h=48t-16t^2. After how many seconds will the rocket hit the ground? Please show all work necessary to arrive to the solution. \n" ); document.write( "

Algebra.Com's Answer #224791 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
The rocket is on the ground when $\"h=0\"$ .
\n" ); document.write( " $\"48t-16t%5E2=0\"$
\n" ); document.write( " $\"t%2848-16t%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"t=0\"$ , The rocket hasn't left yet.
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( " $\"48-16t=0\"$
\n" ); document.write( " $\"16t=48\"$
\n" ); document.write( " $\"t=3\"$
\n" ); document.write( "The rocket will hit the ground in 3 seconds. \n" ); document.write( "

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