document.write( "Question 314422: I could really use some help answering the following question. I have tried to figure it out and I may have figured out parts of it, but not sure how to do all of it. Any help would be much appreciated. Here is the problem:\r
\n" ); document.write( "\n" ); document.write( "8x^2 over x^2-9 multiplied by x^2 + 6x+9 over 16x^3\r
\n" ); document.write( "\n" ); document.write( "I think that x^2 -9 factors down to (x+3)(x-3) and x^2 +6+9 factors down to (x+3)(x+3). I am not sure what to do with 8x^2 and 16x^3. Thank you in advance for any help. \r
\n" ); document.write( "\n" ); document.write( "Tammy \n" ); document.write( "

Algebra.Com's Answer #224764 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
8x^2 over x^2-9 multiplied by x^2 + 6x+9 over 16x^3
\n" ); document.write( "-----------------
\n" ); document.write( "(8x^2)/(x^2-9) * (x^2+6x+9)/(16x^3)
\n" ); document.write( "-----
\n" ); document.write( "Factor to get:
\n" ); document.write( "[8x^2/[(x-3)(x+3)] * [(x+3)^2/(16x^3)]
\n" ); document.write( "-----
\n" ); document.write( "Cancel any factor common to a numerator and a denominiator,
\n" ); document.write( "such as 8,x^2,(x+3), to get:
\n" ); document.write( "---
\n" ); document.write( "[1/(x-3)] * [(x+3)/x]
\n" ); document.write( "---
\n" ); document.write( "Multiply to get:
\n" ); document.write( "= (x/3)/[x(x-3)]
\n" ); document.write( "====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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