document.write( "Question 314409: \"%281%2Fx%29+%2B+%281%2F%281%2Bx%29%29+=+%28%28-3%29%2F%28x%5E2%2Bx%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Hello, can you please help me solve this?
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Algebra.Com's Answer #224762 by Jstrasner(112)\"\" \"About 
You can put this solution on YOUR website!
Hey,
\n" ); document.write( "This shouldn't be too difficult.\r
\n" ); document.write( "\n" ); document.write( "So first all of the denominators have to be the same. So we must multiply each expression by something ont he top and bottom to get the same denominator.\r
\n" ); document.write( "\n" ); document.write( "Therefore:\r
\n" ); document.write( "\n" ); document.write( "the greatest common denominator is (x^2)+x\r
\n" ); document.write( "\n" ); document.write( "Therefore you need to multiply (1/x) by (1+x/1+x) so that the denominator is (x^2+x). You will get (1+x)/((x^2)+x) for the first expression.\r
\n" ); document.write( "\n" ); document.write( "For the second : 1/(1+x), you need to multiply the top and the bottom by x to get:\r
\n" ); document.write( "\n" ); document.write( "x/((x^2)+x)\r
\n" ); document.write( "\n" ); document.write( "Now that all of the expressions have the same denominator, we can change the equation to:\r
\n" ); document.write( "\n" ); document.write( "(1+x)+x=-3\r
\n" ); document.write( "\n" ); document.write( "And from here we get:\r
\n" ); document.write( "\n" ); document.write( "1+2x=-3 => 2x=-4 => x=-2\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps!
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