document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314406>Question 314406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> fimd the sum of the first 30 numbers:6+10+14+18+22 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224757 by </B><A HREF=/tutors/aboutme.mpl?userid=Jstrasner><B>Jstrasner(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jstrasner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jstrasner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok so first this is an arithmetic equation. To find the sum, you would use this formula:\r<BR>\n" );
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document.write( "S(n)=(n/2)(a1+a(n))<BR>\n" );
document.write( "a1 being the first number in the sequence.\r<BR>\n" );
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document.write( "To find the 30th term, we use the definition of a arithmetic series:\r<BR>\n" );
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document.write( "a(n)= a1+(n-1)r    => a(30)=6+29(4)=122\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "s(30)=(30/2)(6+122)= 1920 \r<BR>\n" );
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document.write( "i hope this helps! </SPAN>\n" );
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