document.write( "Question 314364: Let y=x^2+2x-3.Find x when y=0 \n" ); document.write( "
Algebra.Com's Answer #224739 by checkley77(12844) ![]() You can put this solution on YOUR website! y=x^2+2x-3 \n" ); document.write( "x^2+2x-3=0 \n" ); document.write( "(x+3)(x-1)=0 \n" ); document.write( "x+3=0 \n" ); document.write( "x=-3 ans. \n" ); document.write( "x-1=0 \n" ); document.write( "x=1 ans. \n" ); document.write( " |