document.write( "Question 314367: I dont get how to do algabra atttt alllllllllllll!!!
\n" ); document.write( "Please hlp !\r
\n" ); document.write( "\n" ); document.write( "Ill give you an ecasion and can you answer it and tell me how you got the answer \r
\n" ); document.write( "\n" ); document.write( "W/3 + 6 = 2
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Algebra.Com's Answer #224733 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume the problem is:
\n" ); document.write( "\"W%2F3\" + 6 = 2
\n" ); document.write( "remember whatever you do to one side, do also to the other side
\n" ); document.write( "Subtract 6 from both sides
\n" ); document.write( "\"W%2F3\" + 6 - 6 = 2 - 6
\n" ); document.write( "which is
\n" ); document.write( "\"W%2F3\" = -4
\n" ); document.write( "Multiply both sides by 3
\n" ); document.write( "3*\"W%2F3\" = 3 * -4
\n" ); document.write( "cancels the denominator and you have
\n" ); document.write( "W = -12
\n" ); document.write( ":
\n" ); document.write( "Now check the solution in the original equation
\n" ); document.write( "\"%28-12%29%2F3\" + 6 = 2
\n" ); document.write( "-4 + 6 = 2,
\n" ); document.write( "2 = 2, confirms our solution
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