document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36584>Question 36584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The circumference of a circular pond is 840m.Betty walks at a speed of 6m/min and Natalie walks at a speed of 9m/min.If two of start from the same place but walk in opposite directions,how many minutes later will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22472 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of minutes before they meet.\r<BR>\n" );
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document.write( "Betty distance: 6x meters\r<BR>\n" );
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document.write( "Natalie distance: 9x meters\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( " Betty distance + Natale distance = 840<BR>\n" );
document.write( "   6x+9x=840<BR>\n" );
document.write( "    15x = 840<BR>\n" );
document.write( "     x = 56 minutes\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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