document.write( "Question 314304: I am having trouble solving the following problems:\r
\n" ); document.write( "\n" ); document.write( "ln(sqrt(x-8)) = 5\r
\n" ); document.write( "\n" ); document.write( "log4x-log(12+(sqrt x)) = 2\r
\n" ); document.write( "\n" ); document.write( "The number N of trees of a given species per acre is approximated by the model N=68(10^-0.04x), 5 < x < 40, where x is the average diameter of the trees in inches 3 feet above the ground. Use the model to approximate the average diameter of the trees in a test plot when N=21.\r
\n" ); document.write( "\n" ); document.write( "Someone please help!! I cannot figure them out and would GREATLY APPRECIATE IT!!\r
\n" ); document.write( "\n" ); document.write( "THANK YOU!!
\n" ); document.write( "

Algebra.Com's Answer #224699 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
ln(sqrt(x-8)) = 5
\n" ); document.write( "sqrt(x-8) = e^5
\n" ); document.write( "(x-8) = [e^10]
\n" ); document.write( "x = e^10+8
\n" ); document.write( "x = 22034
\n" ); document.write( "-------------------------------
\n" ); document.write( "log4x-log(12+(sqrt x)) = 2
\n" ); document.write( "---
\n" ); document.write( "log[4x/[12+sqrt(x)] = 2
\n" ); document.write( "4x/[12+sqrt(x)] = 10^2
\n" ); document.write( "4x = 1200 + 100sqrt(x)
\n" ); document.write( "x = 300 + sqrt(x)
\n" ); document.write( "---
\n" ); document.write( "x - sqrt(x) - 300 = 0
\n" ); document.write( "---
\n" ); document.write( "Let w = sqrt(x)
\n" ); document.write( "Substitute to get:
\n" ); document.write( "w^2 - w - 300 = 0
\n" ); document.write( "w = [1 +- sqrt(1 - 4*-300)]/2
\n" ); document.write( "---
\n" ); document.write( "Positive solution:
\n" ); document.write( "w = [1 + sqrt(1201)]/2 is approximately 17.8277
\n" ); document.write( "---
\n" ); document.write( "So, sqrt(x) = 17.8277
\n" ); document.write( "x = 317.83
\n" ); document.write( "------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "The number N of trees of a given species per acre is approximated by the model N=68(10^-0.04x), 5 < x < 40, where x is the average diameter of the trees in inches 3 feet above the ground. Use the model to approximate the average diameter of the trees in a test plot when N=21.
\n" ); document.write( "----------------
\n" ); document.write( "N=68(10^-0.04x)
\n" ); document.write( "21 = 68(10^(-0.04x)
\n" ); document.write( "0.3088 = 10^(-0.04x)
\n" ); document.write( "Take the log of both sides to get:
\n" ); document.write( "-0.04x = log(0.3088)
\n" ); document.write( "x = 12.76 inches
\n" ); document.write( "========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "========================
\n" ); document.write( "
\n" );