document.write( "Question 314330: Paul is 7 years younger than Carol. Three years from now, she will be twice as old as he will be. How old is each now?
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document.write( " Paul Carol
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document.write( "My work Paul is NOW: x-7 & three years from NOW would be x-7/2.
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document.write( "Carol is NOW: x & three years from NOW would be 2(x-7). \r
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document.write( "I got this answer: x-7 = 2(x-7)
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document.write( " x-7 = 2x-14
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document.write( " 7=x \n" );
document.write( "
Algebra.Com's Answer #224688 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! x=Carol now \n" ); document.write( "x-7 = Paul now\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+3= Carol in 3 years \n" ); document.write( "x-7+3=x-4= paul in 3 years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+3=2(x-4)\r \n" ); document.write( "\n" ); document.write( "x+3=2x-8 \n" ); document.write( "-x=-11 \n" ); document.write( "x=11 Carol now \n" ); document.write( "x-7= 4 Paul now\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: In 3 years, Carole will be 14 and Paul will be 7. Carol will indeed be twice as old as Paul.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired \n" ); document.write( " |