document.write( "Question 314234: A manufacturer produces two models of the same toy; Model A and Model B. Model A takes 4 hours to produce and costs $8/each. Model B takes 3 hours to produce and costs $7/each. If the manufacturer allots a total of 5800 hours and $12,600 for production each week, how many of each model will be produced?\r
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Algebra.Com's Answer #224679 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let the number of toys of Model A produced be x \n" ); document.write( "Let the number of toys of Model B produced be y \n" ); document.write( ".. \n" ); document.write( "time equation \n" ); document.write( "4x+3y=5800 \n" ); document.write( "Cost equation \n" ); document.write( "8x+7y=12600 \n" ); document.write( ".. \n" ); document.write( "Multiply the first equation by 2 and subtract the second to eliminate x. \n" ); document.write( "8x+6y-8x-7y=11600-12600 \n" ); document.write( "-y=-1000 \n" ); document.write( "y= 1000 Number of toys of Model B \n" ); document.write( "plug the value of y in the first equation \n" ); document.write( "4x+3*1000= 5800 \n" ); document.write( "4x=5800-3000 \n" ); document.write( "x= 2800/ 4= 700 \n" ); document.write( "Number of toys of Model A= 700\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |