document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314274>Question 314274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of twice a positive integer and 4 times the reciprocal of the integer is 9. Find the integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224663 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n = the number we want to find.\r<BR>\n" );
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document.write( "2n + 4(1/n) = 9\r<BR>\n" );
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document.write( "To remove the fraction, multiply both sides of the equation by n.\r<BR>\n" );
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document.write( "We get 2n^2 + 4 = 9n.\r<BR>\n" );
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document.write( "Subtract 9n from both sides of the equation.\r<BR>\n" );
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document.write( "2n^2 - 9n + 4 = 0\r<BR>\n" );
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document.write( "We now have a quadratic equation.\r<BR>\n" );
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document.write( "Can you find n now? </SPAN>\n" );
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