document.write( "Question 314175: A decorator plans to place a rug in a room 9 m by 12 m in such a way that a uniform strip of flooring around the rug will remain uncovered. If the rug is to cover half the floor space, what should the dimensions of the rug be? \n" ); document.write( "
Algebra.Com's Answer #224657 by checkley77(12844)\"\" \"About 
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9*12=108 YDS^2 IS THE ROOM AREA.
\n" ); document.write( "108/2=54 YDS^2 IS 1/2 THE ROOM AREA.
\n" ); document.write( "(9-2X)(12-2X)=54
\n" ); document.write( "108-24X-18X+4X^2=54
\n" ); document.write( "4X^2-42X+108-54=0
\n" ); document.write( "4X^2-42X+54=0
\n" ); document.write( "(2X-18)(2X-3)=0
\n" ); document.write( "2X-3=0
\n" ); document.write( "2X=3
\n" ); document.write( "X=3/2
\n" ); document.write( "X=1.5
\n" ); document.write( "(9-2*1.5)(12-2*1.5)=54
\n" ); document.write( "(9-3)(12-3)=54
\n" ); document.write( "6*9=54
\n" ); document.write( "54=54
\n" ); document.write( "THE RUG SHOULD BE 6 BY 9 YDS.
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