document.write( "Question 314175: A decorator plans to place a rug in a room 9 m by 12 m in such a way that a uniform strip of flooring around the rug will remain uncovered. If the rug is to cover half the floor space, what should the dimensions of the rug be? \n" ); document.write( "
Algebra.Com's Answer #224657 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 9*12=108 YDS^2 IS THE ROOM AREA. \n" ); document.write( "108/2=54 YDS^2 IS 1/2 THE ROOM AREA. \n" ); document.write( "(9-2X)(12-2X)=54 \n" ); document.write( "108-24X-18X+4X^2=54 \n" ); document.write( "4X^2-42X+108-54=0 \n" ); document.write( "4X^2-42X+54=0 \n" ); document.write( "(2X-18)(2X-3)=0 \n" ); document.write( "2X-3=0 \n" ); document.write( "2X=3 \n" ); document.write( "X=3/2 \n" ); document.write( "X=1.5 \n" ); document.write( "(9-2*1.5)(12-2*1.5)=54 \n" ); document.write( "(9-3)(12-3)=54 \n" ); document.write( "6*9=54 \n" ); document.write( "54=54 \n" ); document.write( "THE RUG SHOULD BE 6 BY 9 YDS. \n" ); document.write( " \n" ); document.write( " |