document.write( "Question 314193: Martine leaves home at 9 a.m., bicycling at a rate of 24 mi/hr. Two hours later, John leaves, driving at the rate of 48 mi/hr. At what time will John catch up with Martine? \n" ); document.write( "
Algebra.Com's Answer #224654 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "D=24T FOR MARTINE
\n" ); document.write( "D=48(T-2) FOR JOHN
\n" ); document.write( "24T=48(T-2)
\n" ); document.write( "24T=48T-96
\n" ); document.write( "24T-48T=-96
\n" ); document.write( "-24T=-96
\n" ); document.write( "T=-96/-24
\n" ); document.write( "T=4 HOURS AFTER 9:00 AM THEY WILL MEET.\r
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