document.write( "Question 314193: Martine leaves home at 9 a.m., bicycling at a rate of 24 mi/hr. Two hours later, John leaves, driving at the rate of 48 mi/hr. At what time will John catch up with Martine? \n" ); document.write( "
Algebra.Com's Answer #224654 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=24T FOR MARTINE \n" ); document.write( "D=48(T-2) FOR JOHN \n" ); document.write( "24T=48(T-2) \n" ); document.write( "24T=48T-96 \n" ); document.write( "24T-48T=-96 \n" ); document.write( "-24T=-96 \n" ); document.write( "T=-96/-24 \n" ); document.write( "T=4 HOURS AFTER 9:00 AM THEY WILL MEET.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |