document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36571>Question 36571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ok I have the factors of 12 but i dont know what to do with the 2/3 power.\r<BR>\n" );
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document.write( "log5 (12)^2/3\r<BR>\n" );
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document.write( "factors of 12 (2)(2)(3)   I could figure out the rest but im not sure if the fraction is changed to a decimal or kept the same.  i need to get this.  I have finals next week and I really need some guidance.   Thanks.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22463 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log5 (12)^2/3 \r<BR>\n" );
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document.write( "=(2/3)[log12/log5]<BR>\n" );
document.write( "=(2/3)[1.54395931...]<BR>\n" );
document.write( "=1.029306...<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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