document.write( "Question 314181: Harry has $4000 invested in two savings accounts. One account earns 6% interest per year, and the other pays 7% per year. If his total interest for the year is $264, how much is invested at 7%? \n" ); document.write( "
Algebra.Com's Answer #224618 by Fombitz(32388)\"\" \"About 
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Let A be the amount at 6% and B be the amount at 7%.
\n" ); document.write( "Total amount
\n" ); document.write( "1.\"A%2BB=4000\"
\n" ); document.write( "Total interest
\n" ); document.write( "\"0.06A%2B0.07B=264\"
\n" ); document.write( "\"6A%2B7B=26400\"
\n" ); document.write( "Multiply eq.1 by (-6) and add to eq. 2,
\n" ); document.write( "\"-6A-6B%2B6A%2B7B=-24000%2B26400\"
\n" ); document.write( "\"highlight_green%28+B=2400%29\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"highlight_green%28+A=1600%29\"
\n" ); document.write( "He has $1600 invested at 6%, $2400 invested at 7%.
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