document.write( "Question 314189: divide (x^3-3x^2-3)/(x-2) \n" ); document.write( "

Algebra.Com's Answer #224602 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
First multiplier : $\"x%5E2\"$
\n" ); document.write( " $\"x%5E2%2A%28x-2%29=x%5E3-2x%5E2\"$
\n" ); document.write( "Subtract from the original polynomial to get the remainder,
\n" ); document.write( " $\"%28x%5E3-3x%5E2-3%29-%28x%5E3-2x%5E2%29=-x%5E2-3\"$
\n" ); document.write( "Next multiplier : $\"-x\"$
\n" ); document.write( " $\"-x%28x-2%29=-x%5E2%2B2x\"$
\n" ); document.write( "Subtract from the remainder to get the new remainder,
\n" ); document.write( " $\"%28-x%5E2-3%29-%28-x%5E2%2B2x%29=-2x-3\"$
\n" ); document.write( "Last multiplier: $\"-2\"$
\n" ); document.write( " $\"-2%28x-2%29=-2x%2B4\"$
\n" ); document.write( "Subtract from the remainder to get the new remainder,
\n" ); document.write( " $\"%28-2x%2B4%29-%28-2x%2B4%29=-7\"$
\n" ); document.write( "Put it all together with the final remainder,
\n" ); document.write( " $\"%28x%5E3-3x%5E2-3%29%2F%28x-2%29=%28x%5E2-x-2%29-7%2F%28x-2%29\"$ \n" ); document.write( "

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