document.write( "Question 36562: 1) A square piece of paper is folded in half vertically. If the resulting figure has a perimeter of 12 cm, what was the area of the original square?\r
\n" ); document.write( "\n" ); document.write( "2) Find the value of the digit A if the 5-digit number 12A3B is divisible by both 4 and 9, and A=/B (The sign between the A and B is actually an equal sign with a slash going through it, not sure what it means).\r
\n" ); document.write( "\n" ); document.write( "3) What is the sum of the digits used to form the integers from 45 to 100, inclusive?\r
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Algebra.Com's Answer #22459 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1) A square piece of paper is folded in half vertically. If the resulting figure has a perimeter of 12 cm, what was the area of the original square?
\n" ); document.write( "Let the square have sides of \"s\" before the folding.
\n" ); document.write( "After the folding the sides are s,s,s/2,s/2
\n" ); document.write( "The perimeter of the resulting rectangle is 3s=12 cm.
\n" ); document.write( "Then s=4 cm
\n" ); document.write( "The area of the original square is 4^2 = 16 cm^2\r
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\n" ); document.write( "\n" ); document.write( "2) Find the value of the digit A if the 5-digit number 12A3B is divisible by both 4 and 9, and A=/B (The sign between the A and B is actually an equal sign with a slash going through it, not sure what it means). \r
\n" ); document.write( "\n" ); document.write( "If the number is divisible by \"9\" the sum of the digits is 9 or 18 or 27
\n" ); document.write( "or some numtiple of 9.
\n" ); document.write( "If the number is divisible by \"4\" it must be an even number.\r
\n" ); document.write( "\n" ); document.write( "Trying different combinations of digits that meet these criteria you will
\n" ); document.write( "find that A=1 and B=2 is a correct answer.\r
\n" ); document.write( "\n" ); document.write( "3) What is the sum of the digits used to form the integers from 45 to 100, inclusive?
\n" ); document.write( "I assume their is some simple way to do this but I do not know what it is.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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