document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314088>Question 314088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let f(x) = 2x + 5. find the range of f(x) if it has a domain (-1, 0, 3). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224583 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29+=+2x+%2B+5 ALIGN=MIDDLE  ALT=\"f%28x%29+=+2x+%2B+5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28-1%29+=+2%28-1%29%2B+5=-2%2B5=3 ALIGN=MIDDLE  ALT=\"f%28-1%29+=+2%28-1%29%2B+5=-2%2B5=3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%280%29=2%280%29%2B5=5 ALIGN=MIDDLE  ALT=\"f%280%29=2%280%29%2B5=5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%283%29=2%283%29%2B5=6%2B5=11 ALIGN=MIDDLE  ALT=\"f%283%29=2%283%29%2B5=6%2B5=11\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "For the domain of (-1,0,3) the range is (3,5,11). </SPAN>\n" );
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