document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314101>Question 314101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two numbers is 84. The first number is divided by 3 and the second number is multiplied by 4. The product of the two new numbers is then divided by 2. What is the final result of this calculation?\r<BR>\n" );
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document.write( "(A) 14 (B) 24 (C) 42 (D) 56 (E) None of these </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224533 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%2AB+=+84 ALIGN=MIDDLE  ALT=\"A%2AB+=+84\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28A%2F3%29+%2A+%28B%2A4%29%29%2F2+=+AB%2A%284%2F6%29+=+84%2A2%2F3+=+56 ALIGN=MIDDLE  ALT=\"%28%28A%2F3%29+%2A+%28B%2A4%29%29%2F2+=+AB%2A%284%2F6%29+=+84%2A2%2F3+=+56\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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