document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314102>Question 314102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An integer is composed of three digits. The first digit is even. The second digit is six less than the first digit. The third digit is three less than the first. If the integer is not divisible by five,what is the sum of the three digits?\r<BR>\n" );
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document.write( "(A) 9 (B) 11 (C) 12 (D) 15 (E) None of these </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224532 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the integer be represented as XYZ<BR>\n" );
document.write( "You are told X is even - so X can be 0,2,4,6 0r 8<BR>\n" );
document.write( "Y is 6 less than X. Thus X must be either 6 or 8 for Y to be valid<BR>\n" );
document.write( "Z is 3 less than X. So Z is either 3 or 5<BR>\n" );
document.write( "You are told the number is not divisible by 5, so Z cannot be 5. Z must therefore be 3<BR>\n" );
document.write( "Which makes X 3+3 = 6<BR>\n" );
document.write( "Which makes Y 6-6 = 0<BR>\n" );
document.write( "The number is 603<BR>\n" );
document.write( "Total of X+y+Z = 9\r<BR>\n" );
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document.write( "Answer is A </SPAN>\n" );
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