document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314079>Question 314079</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Factor completely 8t^2 + 18t + 9= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224522 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is what I call \"Advanced Trinomial Factoring.\"  Realize that a TRINOMIAL usually factors into the product of two binomials.<BR>\n" );
document.write( "8t^2+8t+9\r<BR>\n" );
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document.write( "The first times first will probably begin with 4t *2t<BR>\n" );
document.write( "(4t+____)(2t+____)\r<BR>\n" );
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document.write( "The last times last will probably be 3*3.  The question is this:  Will your middle term come out to 18t.<BR>\n" );
document.write( "(4t+3)(2t+3)  The middle term is 4t*3 + 3*2t, which is 12t +6t, which is correct 18t, and this is correct.\r<BR>\n" );
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document.write( "Final answer (4t+3)(2t + 3) </SPAN>\n" );
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