document.write( "Question 313783: if the area of a circle is equal to the area of an equilateral triangle , then the ratio of the side of the triangle to the radius of the circle is closest to which number ?\r
\n" ); document.write( "\n" ); document.write( "a 3 b 4 c 5 d 6 e 7
\n" ); document.write( "

Algebra.Com's Answer #224509 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
if the area of a circle is equal to the area of an equilateral triangle,
\n" ); document.write( " then the ratio of the side of the triangle to the radius of the circle is closest to which number?
\n" ); document.write( ":
\n" ); document.write( "Choose a value for the area; A = 60
\n" ); document.write( "\"pi%2Ar%5E2\" = 60
\n" ); document.write( "r^2 = \"60%2Fpi\"
\n" ); document.write( "r = \"sqrt%2819.1%29\"
\n" ); document.write( "r = 4.37 is the radius
\n" ); document.write( ":
\n" ); document.write( "The triangle (s=side)
\n" ); document.write( "\"1%2F2\"*s*h = 60
\n" ); document.write( "Find the height of the triangle in terms of s
\n" ); document.write( "h = \"sqrt%28s%5E2+-+%28.5s%29%5E2%29\"
\n" ); document.write( "h = \"sqrt%28s%5E2+-+.25s%5E2%29\"
\n" ); document.write( "h = \"sqrt%28.75s%5E2%29\"
\n" ); document.write( "Area of the triangle
\n" ); document.write( "\"1%2F2\"*s*h = 60
\n" ); document.write( "s * h = 120; mult both sides by 2
\n" ); document.write( "Replace h with \"sqrt%28.75s%5E2%29\"
\n" ); document.write( "s * \"sqrt%28.75s%5E2%29\" = 120
\n" ); document.write( "Square both sides
\n" ); document.write( "s^2 * .75s^2 = 14400
\n" ); document.write( ".75s^4 = 14400
\n" ); document.write( "s^4 = \"14400%2F.75\"
\n" ); document.write( "s^4 = 19200
\n" ); document.write( "Find the 4th root of both sides
\n" ); document.write( "s = 19200^(1/4)
\n" ); document.write( "s = 11.77 is the side of triangle
\n" ); document.write( ":
\n" ); document.write( "\"11.77%2F4.37\" ~ 2.7, closest to 3
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "seems like there should be a more elegant way to do this, but I can't come up with it.
\n" ); document.write( "
\n" ); document.write( "
\n" );