document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313942>Question 313942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this word problem equation,\r<BR>\n" );
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document.write( "A store mixes Kenyan coffee worth $10 per kilogram and Turkish coffee worth $12 per kilogram.The mixture is to sell for $11 per kilogram.Find how much of each should be used to make a 588-kilogram mixture.\r<BR>\n" );
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document.write( "How many kilograms of the Kenyan coffee should be in the mixture?\r<BR>\n" );
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document.write( "How many kilograms of the Turkish coffee should be in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224468 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12X+10(588-X)=588*11<BR>\n" );
document.write( "12X+5,880-10X=6,468<BR>\n" );
document.write( "2X=6,468-5,880<BR>\n" );
document.write( "2X=588<BR>\n" );
document.write( "X=588/2<BR>\n" );
document.write( "X=294 POUNDS OF $12 COFFEE IS USED.<BR>\n" );
document.write( "588-294=294 LOUNDS OF $10 COFFEE IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "12*294+10*294=588*11<BR>\n" );
document.write( "3,528+2,940=6,468<BR>\n" );
document.write( "6,468=6,468<BR>\n" );
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