document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313958>Question 313958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jimmy is a partner in an Internet-based coffee supplier.The company offers gourmet coffee beans for $13 per pound and regular coffee beans for $4 per pound. Jimmy is creating a  product that will sell for $6 per pound.The first thing to go into the mixing bin was 18 pounds of the gourmet beans. How many pounds of the less expensive regular beans should be added? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224466 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18*13+4X=6(18+X)<BR>\n" );
document.write( "234+4X=108+6X<BR>\n" );
document.write( "4X-6X=108-234<BR>\n" );
document.write( "-2X=-126<BR>\n" );
document.write( "X=-126/-2<BR>\n" );
document.write( "X=63 POUNDS OF $4 COFFEE IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "18*13+4*63=6(18+63)<BR>\n" );
document.write( "234+252=6*81<BR>\n" );
document.write( "486=486\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );