document.write( "Question 313974: An investment has grown to $89,000 over a 6-year period. The interest was computed daily and the rate was 7 3/8 % per year. What was the original investment?\r
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Algebra.Com's Answer #224461 by checkley77(12844)\"\" \"About 
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X(1+.07375/365)^6*365=89,000
\n" ); document.write( "X(1+.000202)^2,190=89,000
\n" ); document.write( "X(1.000202)^2,190=89,000
\n" ); document.write( "X*1.556=89,000
\n" ); document.write( "X=89,000/1.556
\n" ); document.write( "X=$57,197.94 WAS THE ORIGINAL INVESTMENT.
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