document.write( "Question 313892: Express the confidence interval in the form of P ± E.
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\n" ); document.write( "15) -0.128 < p < 1.212
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Algebra.Com's Answer #224415 by Edwin McCravy(20056)\"\" \"About 
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Express the confidence interval in the form of P ± E.
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\n" ); document.write( " -0.128 < p < 1.212
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document.write( "First find the mean value (average) P of -0.128 and 1.212\r\n" );
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document.write( "\"%28-0.128%2B1.212%29%2F2=1.084%2F2=0.542\"\r\n" );
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document.write( "Then the difference between the mean value P and the lower value\r\n" );
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document.write( "\"0.542-%28-0.128%29=0.542%2B0.128=0.67\"\r\n" );
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document.write( "is the same as the difference between the upper value and the \r\n" );
document.write( "mean value\r\n" );
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document.write( "\"1.212-0.542=0.67\"\r\n" );
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document.write( "and this value is the \"Error\", E.\r\n" );
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document.write( "Thus in the form P ± E, the answer is\r\n" );
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document.write( "0.542 ± 0.67\r\n" );
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document.write( "Edwin
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