document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313815>Question 313815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a square is 81 square centimeters. If the same amount is added to one dimension and removed from the other, the resulting rectangle has an area 9 square centimeters less than the area of the square. How much is added and subtracted? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224391 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "We know that the measure of the square is 9 cm by 9 cm. Let's represent each side as \"x\". Let's represent the amount added and subtracted as \"y\". The equation that can be set up is:<BR>\n" );
document.write( "x^2-9=(x+y)(x-y) This can be rewritten as:<BR>\n" );
document.write( "x^2-9=x^2-y^2 The x^2 cancels out leaving us:<BR>\n" );
document.write( "-9=-y^2 Divide by -1 and sq rt to get:<BR>\n" );
document.write( "y=3<BR>\n" );
document.write( "Therefore we can solve this rectangle size as 12 cm by 6 cm. The area comes out to be 72 cm^2. It works out. <BR>\n" );
document.write( "Makes sense?<BR>\n" );
document.write( "RJ <BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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