document.write( "Question 313757: You have $50,000 and wish to invest part at 10% and the rest at 6%. How much should be invested at each rate to prduce the same return as if it all had been invested at 9%? \n" ); document.write( "
Algebra.Com's Answer #224365 by mananth(16946)\"\" \"About 
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$50000 @9% will yield = $4500 /year\r
\n" ); document.write( "\n" ); document.write( "10% investment = $ x
\n" ); document.write( "6% investment = 50000-x
\n" ); document.write( "..
\n" ); document.write( "interest received = 4500\r
\n" ); document.write( "\n" ); document.write( "0.1x+0.06x=4500
\n" ); document.write( "0.16x=4500
\n" ); document.write( "x= 4500/0.16= $28,125. This will be 10% investment
\n" ); document.write( "Balance will be invested at6% = $21,875
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