document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313587>Question 313587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 11 It is given that -1/2 is a root of the equation 10x^2-9x+k=0, where k is a constant. Find\r<BR>\n" );
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document.write( "(a) the value of k<BR>\n" );
document.write( "(b) the other root </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224346 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  It is given that -1/2 is a root of the equation 10x^2 - 9x + k = 0, where k is a constant.<BR>\n" );
document.write( "A root of -1/2 give us a factor of: (2x + 1)<BR>\n" );
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document.write( "The other factor to satisfy the middle term of -9x: (5x - 7)<BR>\n" );
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document.write( "FOIL (2x + 1)(5x - 7)<BR>\n" );
document.write( "10x^2 - 14x + 5x - 7<BR>\n" );
document.write( "10x^2 - 9x - 7 = 0<BR>\n" );
document.write( " Find<BR>\n" );
document.write( "(a) the value of k<BR>\n" );
document.write( " k = -7<BR>\n" );
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document.write( "(b) the other root<BR>\n" );
document.write( "5x - 7 = 0<BR>\n" );
document.write( "5x = 7<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%2F5 ALIGN=MIDDLE  ALT=\"7%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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