document.write( "Question 313704: \n" ); document.write( "
Algebra.Com's Answer #224334 by r_mr(1)\"\" \"About 
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The length of a rectangle is 4m greater than the width. The area of the rectangle is \"96+m%5E2\". What is the length and the width of the rectangle?\r
\n" ); document.write( "\n" ); document.write( "Let x = length of the rectangle
\n" ); document.write( " y = width of the rectangle
\n" ); document.write( "Representation :
\n" ); document.write( " x = y + 4
\n" ); document.write( " Formula of the area of a rectangle A = lw therefore, A= xy
\n" ); document.write( "Solution:
\n" ); document.write( " A = \"96m%5E2\"
\n" ); document.write( " 96 = y (y + 4)
\n" ); document.write( " 96 = \"y%5E2+%2B+4y\"
\n" ); document.write( " 0 = \"y%5E2+%2B+4y+-+96\"
\n" ); document.write( " 0 = (y + 12) (y - 8)
\n" ); document.write( " 0 = y + 12 | 0 = y - 8
\n" ); document.write( " y = -12 | y = 8
\n" ); document.write( "length and width should not be negative.. the answer for the width is 8m. Length is 4m greater than the width so 8 + 4 = 12m for the length. \r
\n" ); document.write( "\n" ); document.write( "answer :
\n" ); document.write( "x = 12m and y = 8m
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