document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313732>Question 313732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Type A sugar normally costs 75pesos per kilogram. It is mixed with Type B, which normally costs 80 pesos per kilogram, to form a mixture that costs 78pesos per kilogram. If there are 10 kilograms of the mixture, how many kilograms of Type A were used?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224323 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let quantity of type A used be x  price = 75 pesos<BR>\n" );
document.write( "Type B = 10-x kgs. price =80 pesos<BR>\n" );
document.write( "total =10 kg. price =78 pesos<BR>\n" );
document.write( "..<BR>\n" );
document.write( " equate the value of the sugars<BR>\n" );
document.write( "75x+80(10-x)=10*78<BR>\n" );
document.write( "5x+800-80x=780<BR>\n" );
document.write( "-5x=-20<BR>\n" );
document.write( "x=4 kgs - type A <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );