document.write( "Question 313676: bill leaves nightclub at 60mph. sue leaves 1 minute later at 90mph. how many minutes before they meet? \n" ); document.write( "
Algebra.Com's Answer #224304 by checkley77(12844) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=60T FOR BILL. \n" ); document.write( "D=90(T-1/60) FOR SUE. \n" ); document.write( "60T=90(T-1/60) \n" ); document.write( "60T=90T-90/60 \n" ); document.write( "60T-90T=-1.5 \n" ); document.write( "-30T=-1.5 \n" ); document.write( "T=-1.5/-30 \n" ); document.write( "T=.05 HOURS OR IN 3 MINUTES SUE WILL CATCH BILL. \n" ); document.write( "PROOF: \n" ); document.write( "60*.05=90(.05-1/60). \n" ); document.write( "3=90(.05-.01667) \n" ); document.write( "3=90*.0333 \n" ); document.write( "3=3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |