document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313613>Question 313613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well. <BR>\n" );
document.write( "The length of a rectagle is 2 cm. more than 3 times its width. If the area of the rectange is 95 cm^2, find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224298 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W+2<BR>\n" );
document.write( "A=LW<BR>\n" );
document.write( "95=(3W+2)W<BR>\n" );
document.write( "95=3W^2+2W<BR>\n" );
document.write( "3W^2+2W-95=0<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "W=(-2+-SQRT[2^2-4*3*-95])/2*3<BR>\n" );
document.write( "W=(-2+-SQRT[4+1,140])/6<BR>\n" );
document.write( "W=(-2+-SQRT1,144)/6<BR>\n" );
document.write( "W=(-2+-33.823)/6<BR>\n" );
document.write( "W=(-2+33.823)/6<BR>\n" );
document.write( "W=31.823/6<BR>\n" );
document.write( "W=5.304 ANS.<BR>\n" );
document.write( "W=(-2-33.823)/6<BR>\n" );
document.write( "W=-35.823/6<BR>\n" );
document.write( "W=-5.967 ANS. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );