document.write( "Question 313614: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well.
\n" ); document.write( "A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 15ft by 25ft. The total area, garden plus walkway, is to be 650ft^2. What must be the width of the walkway? \n" ); document.write( "
Algebra.Com's Answer #224294 by checkley77(12844)\"\" \"About 
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(15+2X)(25+2X)=650
\n" ); document.write( "375+50X+30X+4X^2=650
\n" ); document.write( "4X^2+80X+375-650=0
\n" ); document.write( "4X^2+80X-275=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=(-80+-SQRT[80^2-4*4*-275])/2*4
\n" ); document.write( "X=(-80+-SQRT[6,400+4,400])/8
\n" ); document.write( "X=(-80+-SQRT10,800)/8
\n" ); document.write( "X=(-80+-103.923)/8
\n" ); document.write( "X=(-80+103.923)/8
\n" ); document.write( "X=23.923/8
\n" ); document.write( "X=2.99 ANS. FOR THE WIDTH OF THE WALKWAY.\r
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