document.write( "Question 313509: The probability that brand A coffeemaker will brew bitter coffee is 0.3 and the probability that brand B coffeemaker will brew bitter coffee is 0.2. Two cups of coffee are produced; one by coffeemaker A and the other by coffeemaker B. Find the probability that:\r
\n" ); document.write( "\n" ); document.write( "(a) Both cups of coffee are bitter. \r
\n" ); document.write( "\n" ); document.write( "(b) Only the cup from brand A is bitter. \r
\n" ); document.write( "\n" ); document.write( "(c) Exactly one cup is bitter. \r
\n" ); document.write( "\n" ); document.write( "(d) Neither cups of coffee is bitter.\r
\n" ); document.write( "\n" ); document.write( "Please help. My brain is dead and this is my last question on the homework. Here's what I got, but I don't think it's correct:
\n" ); document.write( "(a) .2 x .3 = .06 or 6%
\n" ); document.write( "(b) .3 or 30%
\n" ); document.write( "(c) ?
\n" ); document.write( "(d) .7 x .8 = .56 or 56%
\n" ); document.write( "
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Algebra.Com's Answer #224291 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The probability that brand A coffeemaker will brew bitter coffee is 0.3 and the probability that brand B coffeemaker will brew bitter coffee is 0.2. Two cups of coffee are produced; one by coffeemaker A and the other by coffeemaker B. Find the probability that:
\n" ); document.write( "(a) Both cups of coffee are bitter.
\n" ); document.write( "(b) Only the cup from brand A is bitter.
\n" ); document.write( "(c) Exactly one cup is bitter.
\n" ); document.write( "(d) Neither cups of coffee is bitter.
\n" ); document.write( "Please help. My brain is dead and this is my last question on the homework. Here's what I got, but I don't think it's correct:
\n" ); document.write( "(a) .2 x .3 = .06 or 6%
\n" ); document.write( "OK
\n" ); document.write( "--------
\n" ); document.write( "(b) .3 or 30%
\n" ); document.write( "No: 0.3*0.8 = 0.24 or 24%
\n" ); document.write( "---------------------------------
\n" ); document.write( "(c) ?
\n" ); document.write( "P(neither bitter) = 0.7*0.8 = 0.56
\n" ); document.write( "P(both bitter) = 0.2*0.3 = 0.06
\n" ); document.write( "P(one bitter) = 1 - (0.56+0.06) = 1-0.62 = 0.38
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\n" ); document.write( "(d) .7 x .8 = .56 or 56%
\n" ); document.write( "OK
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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