document.write( "Question 313509: The probability that brand A coffeemaker will brew bitter coffee is 0.3 and the probability that brand B coffeemaker will brew bitter coffee is 0.2. Two cups of coffee are produced; one by coffeemaker A and the other by coffeemaker B. Find the probability that:\r
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document.write( "(a) Both cups of coffee are bitter. \r
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document.write( "(b) Only the cup from brand A is bitter. \r
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document.write( "(c) Exactly one cup is bitter. \r
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document.write( "(d) Neither cups of coffee is bitter.\r
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document.write( "Please help. My brain is dead and this is my last question on the homework. Here's what I got, but I don't think it's correct:
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document.write( "(a) .2 x .3 = .06 or 6%
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document.write( "(b) .3 or 30%
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document.write( "(c) ?
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document.write( "(d) .7 x .8 = .56 or 56%
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Algebra.Com's Answer #224291 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The probability that brand A coffeemaker will brew bitter coffee is 0.3 and the probability that brand B coffeemaker will brew bitter coffee is 0.2. Two cups of coffee are produced; one by coffeemaker A and the other by coffeemaker B. Find the probability that: \n" ); document.write( "(a) Both cups of coffee are bitter. \n" ); document.write( "(b) Only the cup from brand A is bitter. \n" ); document.write( "(c) Exactly one cup is bitter. \n" ); document.write( "(d) Neither cups of coffee is bitter. \n" ); document.write( "Please help. My brain is dead and this is my last question on the homework. Here's what I got, but I don't think it's correct: \n" ); document.write( "(a) .2 x .3 = .06 or 6% \n" ); document.write( "OK \n" ); document.write( "-------- \n" ); document.write( "(b) .3 or 30% \n" ); document.write( "No: 0.3*0.8 = 0.24 or 24% \n" ); document.write( "--------------------------------- \n" ); document.write( "(c) ? \n" ); document.write( "P(neither bitter) = 0.7*0.8 = 0.56 \n" ); document.write( "P(both bitter) = 0.2*0.3 = 0.06 \n" ); document.write( "P(one bitter) = 1 - (0.56+0.06) = 1-0.62 = 0.38 \n" ); document.write( "================================== \n" ); document.write( "(d) .7 x .8 = .56 or 56% \n" ); document.write( "OK \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |