document.write( "Question 313679: the perimeter of a rectangle is 24 cm. the area of the same rectangle is 20 sq. cm. find the sides of the rectangle without using calculus. \n" ); document.write( "
Algebra.Com's Answer #224272 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 24=2L+2W \n" ); document.write( "20=LW OR L=20/W \n" ); document.write( "REPLACING L IN THE FIRST EQUATION BY (20/W) & SOLVE FOR W. \n" ); document.write( "24=2(20/W)+2W \n" ); document.write( "24=40/W+2W \n" ); document.write( "24=(40+2W*W)/W \n" ); document.write( "24=(40+2W^2)/W CROSS MULTIPLY. \n" ); document.write( "24*W=40+2W^2 \n" ); document.write( "24W=40+2W^2 \n" ); document.write( "2W^2-24W+40=0 \n" ); document.write( "2(W^2-12W+20)=0 \n" ); document.write( "2(W-10)(W-2)=0 \n" ); document.write( "W-10=0 \n" ); document.write( "W=10 ANS. \n" ); document.write( "L=20/10=2 ANS. \n" ); document.write( "W-2=0 \n" ); document.write( "W=2 ANS. \n" ); document.write( "L=20/2=10 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "20=2*10 \n" ); document.write( "20=20 \n" ); document.write( "24=2*10+2*2 \n" ); document.write( "24=20+4 \n" ); document.write( "24=24 \n" ); document.write( " |