document.write( "Question 313679: the perimeter of a rectangle is 24 cm. the area of the same rectangle is 20 sq. cm. find the sides of the rectangle without using calculus. \n" ); document.write( "
Algebra.Com's Answer #224272 by checkley77(12844)\"\" \"About 
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24=2L+2W
\n" ); document.write( "20=LW OR L=20/W
\n" ); document.write( "REPLACING L IN THE FIRST EQUATION BY (20/W) & SOLVE FOR W.
\n" ); document.write( "24=2(20/W)+2W
\n" ); document.write( "24=40/W+2W
\n" ); document.write( "24=(40+2W*W)/W
\n" ); document.write( "24=(40+2W^2)/W CROSS MULTIPLY.
\n" ); document.write( "24*W=40+2W^2
\n" ); document.write( "24W=40+2W^2
\n" ); document.write( "2W^2-24W+40=0
\n" ); document.write( "2(W^2-12W+20)=0
\n" ); document.write( "2(W-10)(W-2)=0
\n" ); document.write( "W-10=0
\n" ); document.write( "W=10 ANS.
\n" ); document.write( "L=20/10=2 ANS.
\n" ); document.write( "W-2=0
\n" ); document.write( "W=2 ANS.
\n" ); document.write( "L=20/2=10 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "20=2*10
\n" ); document.write( "20=20
\n" ); document.write( "24=2*10+2*2
\n" ); document.write( "24=20+4
\n" ); document.write( "24=24
\n" ); document.write( "
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