document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313623>Question 313623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A straight angle is divided into three smaller angles with measures a, b, and c<BR>\n" );
document.write( "such that  a : b = 3 : 4   c : b = 2 : 1 What is the degree measure of the largest<BR>\n" );
document.write( "angle?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224236 by </B><A HREF=/tutors/aboutme.mpl?userid=OmniMaestra><B>OmniMaestra(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=OmniMaestra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=OmniMaestra><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A straight angle is divided into three smaller angles with measures a, b, and c<BR>\n" );
document.write( "such that  a : b = 3 : 4   c : b = 2 : 1 What is the degree measure of the largest<BR>\n" );
document.write( "angle?\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%2Fb=3%2F4 ALIGN=MIDDLE  ALT=\"a%2Fb=3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%2Fb=1%2F2 ALIGN=MIDDLE  ALT=\"c%2Fb=1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "cross multiply each proportion:<BR>\n" );
document.write( "4a=3b<BR>\n" );
document.write( "2c=b\r<BR>\n" );
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document.write( "put the two equations in a more standard form:<BR>\n" );
document.write( "4a-3b+0c=0<BR>\n" );
document.write( "0a-b+2c=0\r<BR>\n" );
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document.write( "since there are three variables you must have three equations. The third equation is:<BR>\n" );
document.write( "a+b+c=180\r<BR>\n" );
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document.write( "Solve two equations at a time. I'll start with the first and last:\r<BR>\n" );
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document.write( "4a-3b+0c=0----------------------------------------->4a-3b+0c=0<BR>\n" );
document.write( "a+b+c=180------>multiply by 3 to eliminate the b--->3a+3b+3c=540\r<BR>\n" );
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document.write( "Now add down--------------------------------------->7a+___3c=540\r<BR>\n" );
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document.write( "Next, use two different equations and eliminate b.<BR>\n" );
document.write( "0a-b+2c=0<BR>\n" );
document.write( "a+b+c=180\r<BR>\n" );
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document.write( "add down:<BR>\n" );
document.write( "a+___3c=180\r<BR>\n" );
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document.write( "use the two new equations: 7a+3c=540------------------->  7a+3c=540<BR>\n" );
document.write( "--------------------------->a+3c=180-->multipy by -1----> -a-3c=-180\r<BR>\n" );
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document.write( "add down------------------------------------------------->6a=360<BR>\n" );
document.write( "solve for a----------------------------------------------->a=60\r<BR>\n" );
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document.write( "Substitute 60 for a in one of the original equations:\r<BR>\n" );
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document.write( "4a=3b<BR>\n" );
document.write( "4(60)=3b<BR>\n" );
document.write( "240=3b\r<BR>\n" );
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document.write( "divide by 3:   80=b\r<BR>\n" );
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document.write( "So far we know that a=60 and b=80\r<BR>\n" );
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document.write( "substitute 80 for b in one of the original equations:\r<BR>\n" );
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document.write( "2c=b<BR>\n" );
document.write( "2c=80\r<BR>\n" );
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document.write( "solve for c\r<BR>\n" );
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document.write( "c=40\r<BR>\n" );
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document.write( "solution: a=60, b=80, c=40 </SPAN>\n" );
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